Respuesta :

gmany

[tex]a_n=3n-1\\\\for\ n=1\to a_1=3(1)-1=3-1=2\\for\ n=2\to a_2=3(2)-1=6-1=5\\for\ n=3\to a_3=3(3)-1=9-1=8[/tex]

Answer: 2, 5, 8

2,5,8 are the first three terms of the sequence.

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