Question

find the value of n such that the expression is a perfect square trinomial. v2 + 24v + n

Answer 1

$(a+b)^2=a^2+2ab+b^2$

$v^2+24v+n=v^2+2\cdot v\cdot12+n\to n=12^2=144\\\\v^2+2\cdot v\cdot12+12^2=(v+12)^2$

Answer: n = 144

Answer 2

Answer:

144

Step-by-step explanation:

b = 24

(b2)2===(242)2(12)2144

n = 144