Question

Reagent grade potassium hydrogen phthalate (khp, mass 204.23g/mole) is a high molecular weight, stable, monoprotic solid acid. it is commonly used for standardizing sodium hydroxide solutions. what concentration of sodium hydroxide solution would be needed to titration 0.6000g of khp so that the volume of naoh needed is 35.00ml

Answer 1

KHP (aq) + NaOH(aq) ---> KPNa (aq) + H2O(l)

Moles of KHP = $0.600 g KHP * \frac{1 mol KHP}{204.23 g KHP} =0.002938 mol KHP$

Moles of NaOH = $0.002938 mol KHP * \frac{1 mol NaOH}{1 mol KHP} = 0.002938 mol NaOH$

Molarity of NaOH = $0.002900 mol NaOH * \frac{1}{35.00 mL} *\frac{1000mL}{1 L} = 0.08394 M NaOH$