Question

What are the vertical asymptotes of the function f(x) = the quantity of 4 x plus 8, all over x squared plus 3 x minus 4? x = −1 and x = −2 x = −1 and x = 2 x = −1 and x = −4 x = 1 and x = −4

Answer 1

The correct answer is option D which is x = 1 and x = −4 are the vertical asymptotes of the function f(x).

What is a function?

A function is defined as the expression that set up the relationship between the dependent variable and independent variable.

Vertical asymptotes are vertical lines that correspond to the zeroes of the denominator of a rational function.

The vertical asymptotes (which tell me where the graph can not go) will be at the values.

$F(x) = \dfrac{4x +8}{x^2+3x-4}$

if you solve the denominator x should not be equal to zero 0 the values of x in the denominator will be the answer.

Denominator = x² + 3x - 4

                      = ( x² + 4x - x - 4 )

                      = ( x (x+4) - 1( x+4 )

                      = ( x+4 ) ( x-1)

So values of x are ( -4 ) and ( 1 )

Therefore the correct answer is option D which is x = 1 and x = −4 are the vertical asymptotes of the function f(x).

To know more about function follow

https://brainly.com/question/25638609

#SPJ1