As per the problem,
Rhonda bought a new laptop for $800.
The laptop depreciates, or loses, 20% of its value each year.
The value of the laptop at a later time can be found using the formula
[tex] A=P(1-r)^t.....(1) [/tex]
Here we have
P=$800
r=20%=0.20
t=2 years
Substitute the values in equation (1) we get
[tex] A=800(1-0.2)^2\\
\\
\Rightarrow A=800(0.8)^2\\
\\
\Rightarrow A=800*0.64\\
\\
\Rightarrow A=512\\ [/tex]
The laptop be worth in two years will be $512.