Question

Which equivalence factor should you use to convert from 106 grams of diatomic oxygen (O2) to moles of O2? A (1 mol O2/16.00 grams O2) B (16.00 grams O2/1 mol O2) C (1 mol O2/32.00 grams O2) D (32.00 grams O2/1 mol O2)

Answer 1

near133.466O2for the amount

Answer 2

Answer : The correct option is, (C) $\frac{1\text{ mol }O_2}{32.00\text{ grams }O_2}$

Explanation :

As we know that, the molar mass of $O_2$ is 32.00 gram per mole (32 g/mole).

To convert gram into mole, we use the conversion:

We are given the mass of $O_2$ is 106 grams.

Converting this into mole, we get:

As, 32 gram of $O_2$ present in 1 mole of $O_2$

And, 1 gram of $O_2$ present in $\frac{1\text{ mol}O_2}{32.00\text{ grams}O_2}$

So, 106 gram of $O_2$ present in $\frac{1\text{ mol}O_2}{32.00\text{ grams}O_2}\times 106\text{ gram }O_2=3.3125\text{ mole}$

The equivalence factor use to convert gram to mole is, $\frac{1\text{ mol}O_2}{32.00\text{ grams}O_2}$

Hence, correct option is, (C) $\frac{1\text{ mol }O_2}{32.00\text{ grams }O_2}$