Question

For the reaction below, the equilibrium concentrations were found to be [nh3] = 0.250 m ; [h2] = 0.420 m ; [n2] = 0.800 m . give the equilibrium constant expression and use it to calculate the constant. 2 nh3(g) 3 h2(g) + n2(g)

Answer 1

Equation for the decomposition of ammonia :

2NH3->N2+3H2

Equilibrium constant for this equation will be:

Kc=[N2]([H2]^3)/[NH3]^2

As given Concentration of N2=0.800 M

Concentration of H2=0.420 M

Concentration of NH3=0.250 M

So Kc=([0.420]^3) *(0.8)/([0.250]^2)

= 0.9483264

so equilibrium constant will be:

0.9483264