I believe you mean 1.02*10^24 so I did
1.02*10^24/(6.02*10^23) * 54.938. I got d) 9.31*10^1 g as my answer.
Answer: Option (d) is the correct answer.
Explanation:
According to Avogadro's number, every 1 mole of a substance contains [tex]6.022 \times 10^{23}[/tex] atoms or particles.
Now, it is given that there are [tex]1.02 \times 10^{24}[/tex] atoms of manganese are present. Hence, calculate its number of moles as follows.
No. of moles = [tex]\frac{1.02 \times 10^{24}}{6.022 \times 10^{23}}[/tex]
= 1.69 mol
As we know that, number of moles is equal to mass of a substance divided by its molar mass. Since, molar mass of manganese is 54.93 g/mol.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
1.69 mol = [tex]\frac{mass}{54.93 g/mol}[/tex]
mass = 93 g
Therefore, we can conclude that the mass in grams of [tex]1.02 \times 10^{24}[/tex] atoms of manganese (Mn) are [tex]9.31 \times 10^{1} g[/tex].
