The cube below has sides of length 4 feet. If a cylindrical section of radius 2 feet is removed from the solid, what is the total remaining volume of the cube? Express your answer in cubic feet in terms of pi.

The cube below has sides of length 4 feet If a cylindrical section of radius 2 feet is removed from the solid what is the total remaining volume of the cube Exp class=

Respuesta :

Because the main shape is a cube and a cube has all sides equal in length, the volume (l*w*h) is 4*4*4=64.  No pi in that volume.  Just 64 ft^3.  The volume for a cylinder is [tex]V= \pi r^2h[/tex].  The radius is 2 feet and the height is the same as the height of the cube from which it was removed.  So volume for the cylinder is [tex]V= \pi (2)^24[/tex] which is [tex]16 \pi [/tex].  Since we are removing the volume of the cylinder from the volume of the cube, the volume remaining, in terms of pi is [tex]64-16 \pi ft^3[/tex]