Question

What is the percent by mass of 5.0 g of nacl mixed with 80. g of water?

Answer 1

mass of solute (m1) = 5.0 g NaCl

mass of solvent (m2 ) = 80.0 g H2O

T% = ( m1 / m1 + m2 ) * 100

T% = ( 5.0 / 5.0 + 80.0 ) * 100

T% = ( 5.0 / 85.0 ) * 100

T% = 0.0588 * 100

T = 5.88%