Respuesta :
The angle at the center opposite side b must be
[tex]\theta = \dfrac 1 2 \cdot \dfrac{360^\circ}{5} = 36^\circ[/tex]
[tex]\cos \theta = \dfrac{10}{c}[/tex]
[tex]c = \dfrac{10}{\cos 36^\circ} = 12.36[/tex]
Did you know the cosine of [tex]36^\circ[/tex] was half the Golden Ratio? We can actually get an exact answer for this one.
[tex]c =\dfrac{10}{\frac 1 4 (1+\sqrt 5)} = 10(\sqrt 5 - 1)[/tex]
[tex]\theta = \dfrac 1 2 \cdot \dfrac{360^\circ}{5} = 36^\circ[/tex]
[tex]\cos \theta = \dfrac{10}{c}[/tex]
[tex]c = \dfrac{10}{\cos 36^\circ} = 12.36[/tex]
Did you know the cosine of [tex]36^\circ[/tex] was half the Golden Ratio? We can actually get an exact answer for this one.
[tex]c =\dfrac{10}{\frac 1 4 (1+\sqrt 5)} = 10(\sqrt 5 - 1)[/tex]