Respuesta :
I assume the x-y axis are tilted such that the x-axis is parallel to the surface of the hill while the y-axis is perpendicular to it.
In this case, the x-component of the weight is given by:
[tex]W_x =mg \sin \theta[/tex]
where
m is the mass of the car
g is the acceleration of gravity
[tex]\theta[/tex] is the angle of the hill
Substituting numbers into the formula, we find
[tex]W_x=(1150 kg)(9.81 m/s^2)(\sin 8.70^{\circ})=1706 N[/tex]
In this case, the x-component of the weight is given by:
[tex]W_x =mg \sin \theta[/tex]
where
m is the mass of the car
g is the acceleration of gravity
[tex]\theta[/tex] is the angle of the hill
Substituting numbers into the formula, we find
[tex]W_x=(1150 kg)(9.81 m/s^2)(\sin 8.70^{\circ})=1706 N[/tex]
Answer:
0 N
Explanation:
n(x) = 0
the normal force is not what makes the object move. it is the weight and force exerted along with the tilt of the plane. the Normal force has an x component of 0.