Respuesta :
Hello!
In a rectangle opposite sides are equal. Therefore we have below.
11+11+24+24=70
Therefore, the perimeter cannot be 60 when the width is 11 units.
I hope this helps!
In a rectangle opposite sides are equal. Therefore we have below.
11+11+24+24=70
Therefore, the perimeter cannot be 60 when the width is 11 units.
I hope this helps!
No, the perimeter cannot be 60 units when the width is 11 units if the length is 24 units.
We know that the perimeter of a rectangle = 2(length) + 2(width)
If we plug in the values for the length, width, and perimeter, we get:
60 = 2(24) + 2(11)
If we simplify the right side of the equation by multiplying out the coefficients and adding together the remaining terms, we get:
60 = 48 + 22
60 = 70
Therefore, because 60 is not equal to 70, the rectangle cannot have these dimensions.
Hope this helps!
We know that the perimeter of a rectangle = 2(length) + 2(width)
If we plug in the values for the length, width, and perimeter, we get:
60 = 2(24) + 2(11)
If we simplify the right side of the equation by multiplying out the coefficients and adding together the remaining terms, we get:
60 = 48 + 22
60 = 70
Therefore, because 60 is not equal to 70, the rectangle cannot have these dimensions.
Hope this helps!
