Respuesta :
The mass of 2.60 x10^22 molecules of NaOH is 1.728 grams
calculation
mass = moles x molar mass
molar mass = 40 g/mol
mole is calculated using the Avogadro law
that is 1 mole = 6.02 x10^23 molecules
? = 2.60 x10 ^ 22 molecules
by cross multiplication
(1 mole x 2.60 x10^22) / 6.02 x0^23 = 0.0432 moles
mass is therefore= 0.0432 mole x 40 g/mol = 1.728 grams
calculation
mass = moles x molar mass
molar mass = 40 g/mol
mole is calculated using the Avogadro law
that is 1 mole = 6.02 x10^23 molecules
? = 2.60 x10 ^ 22 molecules
by cross multiplication
(1 mole x 2.60 x10^22) / 6.02 x0^23 = 0.0432 moles
mass is therefore= 0.0432 mole x 40 g/mol = 1.728 grams
Answer : Mass would be = 1.859 g for NaOH
Explanation : We have got [tex]2.88 X 10^{22} [/tex] molecules of NaOH,
so we get,
[tex] \frac{2.88 X 10^{22} moles of NaOH }{6.022 X 10^{23}/mol } X 40.0 [/tex] g of NaOH/mol
On solving we get, answer as 1.859 g
Hence the g of NaOH will be 1.86.
Explanation : We have got [tex]2.88 X 10^{22} [/tex] molecules of NaOH,
so we get,
[tex] \frac{2.88 X 10^{22} moles of NaOH }{6.022 X 10^{23}/mol } X 40.0 [/tex] g of NaOH/mol
On solving we get, answer as 1.859 g
Hence the g of NaOH will be 1.86.