Question

From the 6 male and 10 female sales representatives for an insurance​ company, a team of 3 men and 2 women will be selected to attend a national conference on insurance fraud. In how many ways can the team of 5 be​ selected?

Answer 1

We'll find the answer by multiply "6 choose 3" by "10 choose 2". Let the number of ways we can choose be w.

w = C(6, 3) * C(10, 2)
We can use this formula to solve the combinations.
$C(n, r) =  \frac{n!}{r!(n-r)!}$
w = 20 * 45
w = 900

So there are 900 ways to create a group of people to go to the conference.