[tex]\bf \qquad \textit{Amount for Exponential Decay}
\\\\
A=P(1 - r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &3600\\
r=rate\to 32\%\to \frac{32}{100}\to &0.32\\
t=\textit{elapsed time}\to &5\\
\end{cases}
\\\\\\
A=3600(1-0.32)^5\implies A=3600(0.68)^5\implies A\approx 523.41601[/tex]
