Question

Znco3 has a molar mass of 125.40 g/mol. which of the conversion factors shown below correctly expresses this relationship as well as the relationship between molar mass and the number of formula units of the compound? avogadro's number is 6.022 × 1023.

Answer 1

Answer : $ZnCO_{3}$ will be 1 mole of $ZnCO_{3}$ / 125. 40 g of $ZnCO_{3}$

Explanation : The molar mass and the formula units are the same thing in any compound so when given a molar mass of compound then one mole of that compound is divided by its molar mass. Where one mole will be equal to avogadro's number which is 6.022 X $10^{23}$.

Answer 2

Answer:

the correct expression is 125.4 g ZnCO3 * 1 mol ZnCO3/6.022x10^23 formula units ZnCO3

Explanation:

The conversion factor that correctly expresses the relationship between the molar mass and the number of formula units of the compound is as follows.

Avogadro's number is defined as 6.022x10^23 particles/mole, therefore the conversion would be equal to:

125.4 g ZnCO3 * 1 mol ZnCO3/6.022x10^23 formula units ZnCO3