Respuesta :
[tex]\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-3})\qquad \qquad \qquad
slope = m \implies \cfrac{1}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-3)=\cfrac{1}{2}(x-6)\implies y+3=\cfrac{1}{2}(x-6)[/tex]
Answer: y + 3 = one half(x − 6)
Step-by-step explanation:
The equation of a line in point slope form with slope m and passing through point (a,b) is given by :-
[tex](y-b)=m(x-a)[/tex]
Given : The slope of the line : [tex]m=\dfrac{1}{2}[/tex]
The point from which line is passing : (a,b) = (6,-3)
Then , the point slope form of the given line will be :-
[tex](y-(-3))=\dfrac{1}{2}(x-6)\\\\\Rightarrow\(y+3)=\dfrac{1}{2}(x-6)[/tex]
Hence, the required equation is y + 3 = one half(x − 6)