Choose the point-slope form of the equation below that represents the line that passes through the point (6, −3) and has a slope of one half.

y − 6 = one half(x + 3)
y = one halfx − 6
y + 3 = one half(x − 6)
x − 2y = 12

Respuesta :

[tex]\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-3})\qquad \qquad \qquad slope = m \implies \cfrac{1}{2} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-3)=\cfrac{1}{2}(x-6)\implies y+3=\cfrac{1}{2}(x-6)[/tex]

Answer: y + 3 = one half(x − 6)

Step-by-step explanation:

The equation of a line  in point slope form with slope m and passing through point (a,b) is given by :-

[tex](y-b)=m(x-a)[/tex]

Given : The slope of the line : [tex]m=\dfrac{1}{2}[/tex]

The point from which line is passing : (a,b) = (6,-3)

Then , the point slope form of the given line will be :-

[tex](y-(-3))=\dfrac{1}{2}(x-6)\\\\\Rightarrow\(y+3)=\dfrac{1}{2}(x-6)[/tex]

Hence, the required equation is y + 3 = one half(x − 6)

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