we know h(x) is -(1/4)x-1 only for those values x ≠ 1.
h(-3) simply means x = -3, and since -3 ≠ 1, then we use the subfunction -(1/4)x-1
[tex]\bf h(-3)\implies -\cfrac{1}{4}(-3)-1\implies -\cfrac{-3}{4}-1\implies \cfrac{3}{4}-1\implies \boxed{-\cfrac{1}{4}}[/tex]
h(4) simply means x = 4, and since 4 ≠ 1, then we use the subfunction -(1/4)x-1
[tex]\bf h(4)\implies -\cfrac{1}{4}(4)-1\implies -\cfrac{4}{4}-1\implies -1-1\implies \boxed{-2}[/tex]
h(1) simply means x = 1, wait just a second!! we know that when x = 1, h(x) is using the constant of -3.
[tex]\bf h(1)=\boxed{-3}[/tex]