Respuesta :

ANSWER

3∛(4)

EXPLANATION
108 prime factorizes into 2^2 * 3^3

[tex] \sqrt[3]{108} = \sqrt[3]{2^2 \cdot 3^3}[/tex]

Apply radical property [tex]\sqrt[n]{ab} = \sqrt[n]{a} \cdot \sqrt[n]{b}[/tex]

   [tex]\begin{aligned} \sqrt[3]{108} &= \sqrt[3]{2^2} \cdot \sqrt[3]{ 3^3} \\ &= \sqrt[3]{2^2} \cdot 3 \\ &= 3 \sqrt[3]{4} \end{aligned}[/tex]
Hi there!

Prime factors [ 108 ] = 2² × 3³

[tex]\sqrt[3]{108}[/tex] = [tex]\sqrt[3]{2^{2} × 3^{3}}[/tex]

Apply radical property :-

[tex]\sqrt[n]{ab} = \sqrt[n]{a} × \sqrt[n]{b}[/tex]

[tex]\begin{aligned} \sqrt[3]{108} &= \sqrt[3]{2^2} × \sqrt[3]{ 3^3} \\ &= \sqrt[3]{2^2} × 3 \\ &= 3 \sqrt[3]{4} \end{aligned}[/tex]

~ Hope it helps!
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