the complete question in the attached figure
we know that
To multiply powers with the same base, keep the base and adds the exponent
so
Part 1)
[tex]13 ^{-11} *13 ^{16}*13 ^{-3}*13 ^{4}*13 ^{-5} \\ =13 ^{(-11+16-3+4-5)} \\= 13 ^{1} [/tex]
the answer part 1) is
[tex]13 ^{1} [/tex]
Part 2)
[tex]13 ^{-21} *13 ^{-4}*13 ^{-5}*13 ^{14}*13 ^{-6} \\ =13 ^{(-21-4-5+14-6)} \\= 13 ^{-22} [/tex]
the answer part 2) is
[tex]13 ^{-22} [/tex]
Part 3)
[tex]13 ^{33} *13 ^{-2}*13 ^{5}*13 ^{-13}*13 ^{-8} \\ =13 ^{(33-2+5-13-8)} \\= 13 ^{15} [/tex]
the answer Part 3) is
[tex]13 ^{15}[/tex]
Part 4)
[tex]13 ^{0} *13 ^{10}*13 ^{-12}*13 ^{5}*13 ^{4} \\ =13 ^{(0+10-12+5+4)} \\= 13 ^{7} [/tex]
the answer part 4) is
[tex]13 ^{7}[/tex]