Respuesta :

[tex]\sqrt{-16}+\sqrt{49}=4i+7=7+4i[/tex]

The √-16 + √49 can be written in the complex form as a + ib is 7 + 4i where i is the iota.

What is a complex number?

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

We have:

= √-16 + √49

As we know √-1 = i (iota)

= (√-1)(√16) + √49

√-1 = i

√16 = 4

√49 = 7

= 4i + 7 or

= 7 + 4i

Thus, the √-16 + √49 can be written in the complex form as a + ib is 7 + 4i where i is the iota.

Learn more about the complex number here:

brainly.com/question/10251853

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