Question

Which of the following is equivalent to log 1/9/k

Answer 1

Answer
㏒(1/9) - ㏒K

Explanation
㏒AB =㏒A+B
㏒(A/B) = ㏒A - ㏒B
So, from the log given we will have
㏒(1/9)/K = ㏒(1/9) - ㏒K

Answer 2

Hello!

There is an existing logarithmic property that states that $log \frac{M}{N}$ is equal to $log M-logN$.

Following that property, we can tell that $log \frac{ \frac{1}{9} }{k}$ would be equal to $log \frac{1}{9}-logk$.

ANSWER: $log \frac{1}{9}-logk$ (first option)