Question

the vertex of this parabola is at (-4 -1). when the y-value is 0, the x-value is 2. What is the coefficient of the squares term in the parabola’s equation?

Answer 1

The standard form for this parabola is $x=a(y-k)^2+h$ because this is a sideways-opening parabola.  Our h and k values for the vertex are (-4, -1).  And it goes through (2,0).  We just need to solve for the a.  Filling in accordingly, $2=a(0+1)^2-4$ so 2 = a - 4.  a = 6.  A above.

Answer 2

The correct answer is A