Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-5}{ h},\stackrel{4}{ k})\qquad \qquad radius=\stackrel{3}{ r} \\\\\\\ [x-(-5)]^2+[y-4]^2=3^2\implies (x+5)^2+(y-4)^2=9[/tex]
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