Which table represents a linear function?




Table-1 represents a linear function.
In general, the gradient of the line joining the points A(x₁, y₁) and B(x₂, y₂) is given by the formula:
[tex]\boxed{\boxed{ \ m = \frac{y_2 - y_1}{x_2 - x_1} \ }}[/tex]
Let's examine the slope (m) of each table.
Table-1: (1, 3), (2, 7), (3, 11), (4, 15)
(1, 3) and (2, 7) ⇒ [tex]m = \frac{7-3}{2-1} = 4[/tex]
(2, 7) and (3, 11) ⇒ [tex]m = \frac{11-7}{3-2} = 4[/tex]
(3, 11) and (4, 15) ⇒ [tex]m = \frac{15-11}{4-3} = 4[/tex]
or, we choose (1, 3) and (4, 15) ⇒ [tex]m = \frac{15-3}{4-1} = 4[/tex]
Because it has the same slope of m = 4, this table represents a linear function.
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Table-2: (1, 3), (2, 8), (3, 15), (4, 21)
(1, 3) and (2, 8) ⇒ [tex]m = \frac{8-3}{2-1} = 5[/tex]
(2, 8) and (3, 15) ⇒ [tex]m = \frac{15-8}{3-2} = 7[/tex]
Because it does not have the same slope, this table does not represent a linear function.
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Table-3: (1, 3), (2, 9), (3, 3), (4, 9)
(1, 3) and (2, 9) ⇒ [tex]m = \frac{9-3}{2-1} = 6[/tex]
(2, 9) and (3, 3) ⇒ [tex]m = \frac{3-9}{3-2} = -6[/tex]
Because it does not have the same slope, this table does not represent a linear function.
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Table-4: (1, 3), (2, 9), (3, 27), (4, 81)
(1, 3) and (2, 9) ⇒ [tex]m = \frac{9-3}{2-1} = 6[/tex]
(2, 9) and (3, 27) ⇒ [tex]m = \frac{27-9}{3-2} = 18[/tex]
Because it does not have the same slope, this table does not represent a linear function.
Based on the pattern shown in Table-4, the curve represents the function of [tex]\boxed{y = 3^x}[/tex].
Consider the proof below:
Keywords: which table, represents, a linear function, gradient, slope, rate, straight, points, the formula, m = 4
Table 1 represents the linear function.
Further explanation:
The linear equation with slope [tex]m[/tex] and intercept [tex]c[/tex] is given as follows.
[tex]\boxed{y = mx + c}[/tex]
The formula for slope of line with points [tex]\left( {{x_1},{y_1}} \right)[/tex] and [tex]\left( {{x_2},{y_2}} \right)[/tex] can be expressed as,
[tex]\boxed{m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}}[/tex]
Explanation:
In table 1,
The slope can be obtained as follows,
[tex]\begin{aligned}m &= \frac{{7 - 3}}{{2 - 1}}\\&=\frac{4}{1}\\&= 4\\\end{aligned}[/tex]
The slope of other two points can be obtained as follows,
[tex]\begin{aligned}m&= \frac{{11 - 7}}{{3 - 2}}\\&= \frac{4}{1}\\&= 4\\\end{aligned}[/tex]
The slopes are equal. Therefore, table 1 is correct.
In table 2,
The slope can be obtained as follows,
[tex]\begin{aligned}m&= \frac{{8 - 3}}{{2 - 1}}\\&= \frac{5}{1}\\&=5\\\end{aligned}[/tex]
The slope of other two points can be obtained as follows,
[tex]\begin{aligned}m&= \frac{{15 - 8}}{{3 - 2}}\\&= \frac{7}{1}\\&= 7\\\end{aligned}[/tex]
The slope sare not equal. Therefore, table 2 is not correct.
In table 3,
The slope can be obtained as follows,
[tex]\begin{aligned}m&= \frac{{9 - 3}}{{2 - 1}}\\&= \frac{6}{1}\\&= 6\\\end{aligned}[/tex]
The slope of other two points can be obtained as follows,
[tex]\begin{aligned}m &= \frac{{3 - 9}}{{3 - 2}}\\&=\frac{{ - 6}}{1}\\&=- 6\\\end{aligned}[/tex]
The slopes are not equal. Therefore, table 3 is not correct.
In table 4,
The slope can be obtained as follows,
[tex]\begin{aligned}m &= \frac{{9 - 3}}{{2 - 1}}\\&= \frac{6}{1}\\&= 6\\\end{aligned}[/tex]
The slope of other two points can be obtained as follows,
[tex]\begin{aligned}m&= \frac{{27 - 9}}{{3 - 2}}\\&= \frac{{18}}{1}\\&= 18\\\end{aligned}[/tex]
The slope is not equal. Therefore, table 4 is not correct.
Table 1 represents the linear function.
Learn more:
1. Learn more about collinear points https://brainly.com/question/5795008.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function https://brainly.com/question/3412497
Answer details:
Grade: High School
Subject: Mathematics
Chapter: Linear equation
Keywords: linear function, numbers, slope intercept, inequality, equation, linear inequality, shaded region, y-intercept, graph, representation.