Question

What is the area of one trapezoidal face of the figure?

Answer 1

The area of a trapezoid, A, is the average of the lengths of the bases (B and b) multiplied by the height, h.

$A = \dfrac{(B + b)h}{2}$

$A = \dfrac{(3~in. + 1~in.) \times 1~in.}{2}$

$A = \dfrac{4~in. \times 1~in.}{2}$

$A = \dfrac{4~in.^2}{2}$

$A = 2~in.^2$

Answer 2

Answer:

It is 2 inches squared

Step-by-step explanation:

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