Question

What is the length of EF in the right triangle below?

Answer 1

Length of E F

a² + b² = c²
a² + 7² = 13²
a² + 49 = 169
a² = 169 - 49
a² = 120
a  = √120

Answer = √120

Answer 2

Answer:

(B) $EF=\sqrt{120}$

Step-by-step explanation:

Given: From the figure, it is given that in triangle DEF, DE=13 and DF=7

To find: The value of EF.

Solution: It is given that From the figure, it is given that in triangle DEF, DE=13 and DF=7, therefore using Pythagoras theorem, we have

$(DE)^2=(DF)^2+(EF)^2$

Substituting the given values, we get

$(13)^2=(7)^2+(EF)^2$

$169=49+(EF)^2$

$169-49=(EF)^2$

$120=(EF)^2$

$EF=\sqrt{120}$

Thus, the value of EF is $=\sqrt{120}$.

Hence, option B is correct.