If 0.0225 g of a gas dissolves in 2.73 l of water at 758 torr, at what pressure would you be able to dissolve 0.134 g in the same amount of water?

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PBCHEM
Answer : 4514.311 torr

Explanation : Using henry's law in simplified version;

[tex] \frac{C_{1}}{P_{1}} = \frac{C_{2}}{P_{2}} [/tex]

where [tex] C_{1}[/tex] is the concentration of gas in first case which is 0.0225 g
 and 
[tex] C_{2}[/tex] is the concentration of gas in second case which is 0.134 g

the concentration of water is ignored as it remains the same in both the cases.

And, [tex] P_{1}[/tex] is 758 torr and [tex] P_{2}[/tex] needs to be found.

on substituting the values we get, [tex] P_{2}[/tex] = (0.134 X 758) / 0.0225 = 4514.311 torr

Answer: 4,510

Explanation:

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