Respuesta :
X, X+2, and X+4 are the three odd integers.
2(X)+(X+4)=25 represents the problem.
2X+X+4=25
3X+4=25
3X=25-4
3X=21
X=7
2(X)+(X+4)=25 represents the problem.
2X+X+4=25
3X+4=25
3X=25-4
3X=21
X=7
The three consecutive odd integers : 7, 9, 11
Further explanation
Algebraic expressions in mathematics are a combination of coefficients, numbers, variables, constants and arithmetic operations such as addition, subtraction, multiplication, and division.
The main composition of algebraic expressions are:
• 1. phrases
algebraic forms separated by arithmetic operations
consists of one phrase (monomial) to many phrases (polynomial)
• 2. variable
is a value that can be changed, can be in the form of letters, for example, x, y, a, b, etc.
• 3. constants
is a fixed value, can be a number
• 4. arithmetic operations
+ , - , : , x
integer number: numbers consist of positive, negative and 0 numbers
Odd number: Any integer that cannot be divided by 2.
The last digit is 1, 3, 5, 7 or 9
Because it is divided by 2, the difference between the two numbers is also 2 for consecutive numbers
Then consecutive odd numbers can be symbolized:
x, x + 2, x + 4, x + 6, x + 8, etc.
For example, 3 consecutive odd numbers are:
x + 4, x + 6, x + 8
the sum of the largest and twice the smallest is 25, can be expressed in terms of arithmetic operations:
(x + 8) + 2 (x + 4) = 25
So the solution:
x + 8 + 2x + 8 = 25
3x + 16 = 25
3x = 9
x = 3
So the smallest number is:
= x + 4
= 3 + 4
= 7
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Keywords: arithmetic operations, odd integers,equation
