Find the three consecutive odd integers such that the sum of the largest and twice the smallest is 25. If X represents the smaller integer , then which equation could be used to solve the problem

Respuesta :

X, X+2, and X+4 are the three odd integers.
2(X)+(X+4)=25 represents the problem.
2X+X+4=25
3X+4=25
3X=25-4
3X=21
X=7

The three consecutive odd integers : 7, 9, 11

Further explanation

Algebraic expressions in mathematics are a combination of coefficients, numbers, variables, constants and arithmetic operations such as addition, subtraction, multiplication, and division.

The main composition of algebraic expressions are:

• 1. phrases

algebraic forms separated by arithmetic operations

consists of one phrase (monomial) to many phrases (polynomial)

• 2. variable

is a value that can be changed, can be in the form of letters, for example, x, y, a, b, etc.

• 3. constants

is a fixed value, can be a number

• 4. arithmetic operations

+ , - , : , x

integer number: numbers consist of positive, negative and 0 numbers

Odd number: Any integer that cannot be divided by 2.

The last digit is 1, 3, 5, 7 or 9

Because it is divided by 2, the difference between the two numbers is also 2 for consecutive numbers

Then consecutive odd numbers can be symbolized:

x, x + 2, x + 4, x + 6, x + 8, etc.

For example, 3 consecutive odd numbers are:

x + 4, x + 6, x + 8

the sum of the largest and twice the smallest is 25, can be expressed in terms of arithmetic operations:

(x + 8) + 2 (x + 4) = 25

So the solution:

x + 8 + 2x + 8 = 25

3x + 16 = 25

3x = 9

x = 3

So the smallest number is:

= x + 4

= 3 + 4

= 7

Learn more  

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Keywords: arithmetic operations, odd integers,equation

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