Respuesta :

The answer would be:
[tex] \dfrac{n^{2}-8}{3} [/tex]

This is how it was solved:

[tex] \dfrac{n- \frac{8}{n} }{ \frac{3}{n} } [/tex]

Multiply the numerator and the reciprocal of the denominator. (Following the rules in dividing fractions)

[tex](n-\frac{8}{n})( \frac{n}{3}) [/tex]

Distribution property will yield:
[tex] \dfrac{n^{2}}{3} - \dfrac{8n}{3n} [/tex]

Simplify what you can:

[tex] \dfrac{n^{2}}{3} - \dfrac{8}{3} [/tex]

They have the same denominator, so you can do the operation:

[tex] \dfrac{n^{2}-8}{3} [/tex]
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