Respuesta :
For graph D, the real number is at x = 1 and it goes up the imaginary axis 1 unit so that point is 1 + i. The other point is at x = 2 and goes down the imaginary axis 2 units so that point is 2 - 2i. Therefore, the points connecting that segment are 1+i and 2 - 2i, first choice above. For graph C, the point on the right is at x = 2 and goes down the imaginary axis 1 unit so that point is 2 - i. The point on the left is at x = -1 and goes down the imaginary axis 1 so the point is -1 - i. Therefore, the points connecting that segment are 2 - i and -1 - i. For graph B, the point on the right is at x = 2 and it goes up the imaginary axis 4, so the point is 2 + 4i. For the point on the left, it is at x = -1 and goes up the imaginary axis 2, so the point is -1 + 2i. Therefore, the points connecting that segment are 2 + 4i and -1 + 2i. For graph A, the point on the right is at x = -1 and goes down the imaginary axis 1 so the point is -1-i. The point on the left is at x = -2 and goes up the imaginary axis 1, so the point is -2 + i. The points connecting that segment are -1 - i and -2 + i. There you go!
Graph A- (-1-i, -2+i)
Graph B- (2+4i, -1+2i)
Graph C- (2-i, -1-i)
Graph D- (1+i, 2-2i)
(based off the answer below; not sure if it is fully correct)
Graph B- (2+4i, -1+2i)
Graph C- (2-i, -1-i)
Graph D- (1+i, 2-2i)
(based off the answer below; not sure if it is fully correct)