the molar mass of Pb(NO₃)₂ can be calculated taking the atomic masses of the individual elements
molar masses of the elements
Pb - 207 g/mol
N - 14 g/mol
O - 16 g/mol
molar mass of the compound is the sum of the products of the molar masses by the number of atoms
Pb(NO₃)₂ - 1 x 207 g/mol + 2 x 14 g/mol + 6 x 16 g/mol = 331 g/mol
the mass of 1 mol of Pb(NO₃)₂ has a mass of 331 g
1 mol of Pb(NO₃)₂ contains 6 mol of O
mass of O in 1 mol of Pb(NO₃)₂ is - 96 g
mass percentage of O = mass of O / mass of Pb(NO₃)₂ x 100%
mass % = 96 g / 331 g x 100 % = 29.0 %
mass percentage of O is 29.0%
