Respuesta :

Answer:

[tex]\boxed{\approx 0,438}[/tex]

Step-by-step explanation:

We have the following product:

[tex](5\sqrt{4} - 4\sqrt{3})(5\sqrt{2} -4\sqrt{3})[/tex]

Applying distributive we have the following:

[tex](5\sqrt{4} - 4\sqrt{3})(5\sqrt{2} -4\sqrt{3}) \\ \\ 5 \times \sqrt{4}\sqrt{2}-5\times 4\sqrt{4}\sqrt{3}-4\times 5\sqrt{3}\sqrt{2}+4\times 4\sqrt{3}\sqrt{3}[/tex]

By solving the product of square root we have:

[tex]5 \times5 \sqrt{4}\sqrt{2}-5\times 4\sqrt{4}\sqrt{3}-4\times 5\sqrt{3}\sqrt{2}+4\times 4\sqrt{3}\sqrt{3} \\ \\ 25\sqrt{(4)(2)}-20\sqrt{(4)(3)}-20\sqrt{(3)(2)}+16\sqrt{(3)(3)} \\ \\ 25\sqrt{8}-20\sqrt{12}-20\sqrt{6}+16\sqrt{9}[/tex]

But [tex]\sqrt{9}=3[/tex] then:

[tex]25\sqrt{8}-20\sqrt{12}-20\sqrt{6}+16(3) \\ \\ 25\sqrt{8}-20\sqrt{12}-20\sqrt{6}+48 \approx \boxed{0,438}[/tex]

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