Question

I need half reactions, for the following equation.
Ba + ZnSo4 -> BaSo4 + Zn

I need a oxidation side
and a reduction side

I will be giving brainlist to the first correct answer, do not give me answers from the web, trust me I have already tried

Answer 1

Answer : Half reaction is defined as the reaction which will be either the oxidation or reduction reaction of particular species in a given redox reaction.

So as per the definition in the reaction of,

$Ba + ZnSO_{4} ----\ \textgreater \ BaSO_{4} + Zn$

$Ba_{(s)} + Zn ^{+2} + SO_{4}^{-2} = Ba^{+2} + SO_{4}^{-2} + Zn_{(s)}$

here on left and right side $SO_{4}^{-2}$ will get cancelled.

and we will get, $Ba_{(s)} + Zn ^{+2} = Ba^{+2} + Zn_{(s)}$

Here, 
$Ba_{(s)} ----\ \textgreater \ Ba^{+2} - 2e^{-}$ ...this is oxidation reaction as Ba is getting reduced to $Ba^{+2}$ by losing 2 electrons.

whereas,on the other hand,  $Zn ^{+2} ----\ \textgreater \ Zn_{(s)} + 2e ^{-}$...this is reduction reaction as $Zn ^{+2}$ is getting reduced to Zn by gaining 2 electrons.