Question

how many grams of Silicon (Si, 28.09 g/mol) are in a computer chip with 1.08 x 10^23 atoms of Si

Answer 1

1 mol of any particles - 6.02 *10²³

(1.08*10²³ * 1 mol)/(6.02*10²³) = 1.08*10²³/6.02*10²³ mol Si

(1.08*10²³/6.02*10²³) mol Si * 28.09 g/1mol = (28.09*1.08*10²³)/6.02*10²³ ≈
≈ 5.04 g Si

Answer 2

Answer: 5.04 grams

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given atoms}}{\text {Avogadro's no}}$

For silicon:

Atoms of silicon given = $1.08\times 10^{23}$

Avogadro's number = $6.023\times 10^{23}$

Putting values in above equation, we get:

$\text{Moles of silicon}=\frac{1.08\times 10^{23}}{6.023\times 10^{23}}=0.18mol$

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles

1 mole of $Si$ weighs = 28.09 g

0.18 moles of $Si$ contains =$\frac{28.09}{1}\times 0.18=5.04g$

Thus the mass of silicon in a computer chip is 5.04 grams.