What is the general equation of a sine function with an amplitude of 6, a period of pi/4, and a horizontal shift of pi/2?

A. y = sin ( ( 8 ( x - pi/2 ) )
B. y = 8sin ( ( 4 ( x - pi/2 ) )
C. y= 6sin ( ( 8 ( x - pi/2 ) )
D. y = 6sin (8x) +pi/2

Respuesta :

The formula for the period is [tex] \frac{2 \pi }{b} [/tex] and the formula for the phase shift is [tex] \frac{-c}{b} [/tex], the same b value as in the period.  The general form of the sin function is [tex]y=Asin(bx+c)[/tex], where A is the amplitude. We are given the period as [tex] \frac{ \pi }{4} [/tex], so we will use the formula for the period to solve for b: [tex] \frac{ \pi }{4} = \frac{2 \pi }{b} [/tex].  Cross multiply to get [tex]b \pi =8 \pi [/tex] and b = 8.  Now the phase shift.  We will use the formula for phase shift along with the b value we found to find c.  The phase shift (horizontal shift) is [tex] \frac{ \pi }{2} [/tex], so fitting that into our formula, [tex] \frac{ \pi }{2}= \frac{-c}{8} [/tex].  Cross multiply to get [tex]-2c=8 \pi [/tex] and [tex]c=-4 \pi [/tex].  Now let's put all this together.  [tex]y=6sin(8x-4 \pi )[/tex].  We will factor out the 8 to get the final equation of [tex]y=6sin[8(x- \frac{ \pi }{2})] [/tex], choice C from above.

Answer:

c

Step-by-step explanation:

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