Answer:
Option A
[tex]3,388\pi\ units^{3}[/tex]
Step-by-step explanation:
we know that
The volume of a cone is equal to
[tex]V=\frac{1}{3}\pi r^{2} h[/tex]
where
r is the radius of the base of the cone
h is the height of the cone
In this problem we have
[tex]r=11\ units, h=84\ units[/tex]
substitute the values
[tex]V=\frac{1}{3}\pi (11)^{2}(84)[/tex]
[tex]V=3,388\pi\ units^{3}[/tex]
