live4dramaoy0yf9 live4dramaoy0yf9

26-06-2018
Mathematics

contestada

Find the GCF of the monomials 27x^2 and 81x^5.

Respuesta :

mkryukova19 mkryukova19

26-06-2018

27x² and 81x⁵

81 = 27*3
x⁵ = x²x³

81x⁵ = 27*3*x²x³= (27x²)*3x³

We can see that 81x⁵=(27x²)*3x³ includes as a factor 27x²,
so GCF is 27x².

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