Question

Find K for this redox reaction when E = +1.05 V: Ni + 2Ag+ → Ni2+ + 2Ag

Answer 1

Number of electrons that was displaced in this reaction = 2.
E⁰ = (0.0592/n)log K

log K = (E⁰*n)/0.0592 = 1.05*2/0.0592

K = 10^(1.05*2/0.0592)= 2.97 *10³⁵

Answer 2

Answer:

Yay! Gl with your work! <3