Respuesta :
The common difference is -1-(-7) = 6. Since each term is 6 more than the last, the sequence is described by
a(1) = -7
a(n) = a(n-1) + 6 . . . n ≥ 2
a(1) = -7
a(n) = a(n-1) + 6 . . . n ≥ 2
Answer:
[tex]a_{n}= a_{n-1} + 6[/tex]
Step-by-step explanation:
–7, –1, 5, 11, ......
LEts find out the difference
[tex]-1-(-7)= 6[/tex]
[tex]5-(-1)= 6[/tex]
[tex]11 - 5=6[/tex]
So common difference is 6
General form of recursive for arithmetic sequence is
[tex]a_{n}= a_{n-1} + d[/tex] where d is the common difference
we know common difference d= 6
a_n-1 is the previous term , an is the next term
Recursive formula is 4
[tex]a_{n}= a_{n-1} + 6[/tex]