Question

Juanita begins to factor an expression as shown. x2 + 3x – 18 = (x + )(x – ) The numbers that should be placed in the boxes, from left to right, are 3 and 62 and 96 and 39 and 2

Answer 1

Answer:

The correct option is 3.

Step-by-step explanation:

Let the missing values from left to right are a and b.

The given equation is

$x^2+3x-18=(x+a)(x-b)$

Splitting the middle term we get

$x^2+6x-3x-18=(x+a)(x-b)$

$(x^2+6x)-(3x-18)=(x+a)(x-b)$

Taking out common factors from each parenthesis.

$x(x+6)-3(x+6)=(x+a)(x-b)$

$(x+6)(x-3)=(x+a)(x-b)$

On comparing both sides we get

$a=6,b=3$

The numbers that should be placed in the boxes, from left to right 6 and 3. Therefore the correct option is 3.