Question

The concentration (m) of an aqueous methanol produced when 0.200 l of a 2.00 m solution was diluted to 0.800 l is

Answer 1

Answer : The concentration of the resulting diluted solution will be 0.5 m.

Explanation : As we can see that the mole concentration is given as 2.00 m and the volume is 0.200 L and we need to find the moles in 0.800 L of the diluted solution.

Here the formula of  $m _{1}V_{1}=m_{2} V_{2}$ applies,

so on applying the formula we obtain the value of $m _{2}$ which is unknown in this case, will be :- (0.200 X 2.00) / 0.800 = 0.5 moles.