Question

given the equation 2 square root x-5=2 solve for x and identify if it is an extraneous solution
$2 \sqrt{x - 5} = 2$

Answer 1

2√(x-5) = 2
√(x-5) = 1
x-5 = 1
x=6(I don't know what extraneous solution means though)

Answer 2

Answer: 2√(x-5) = 2

√(x-5) = 1

x-5 = 1

x=6 solution is not extraneous!