Make a two-column proof showing statements and reasons to prove that triangle ABD is similar to triangle ACB.
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Answer with explanation:
In Δ A B D and ΔA CB
1. ⇒ ∠ A is Common.
2.⇒ ∠ABD=∠ACB=45°------[Given]
⇒Δ A B D ~ ΔA CB------[Angle-Angle Similarity Axiom abbreviated as (AA)]