Question

what is the value of x in the equaton
${25}x^{2} = 16$

Answer 1

$25x^2=16\ \ \ |:25\\\\x^2=\dfrac{16}{25}\to x=\pm\sqrt{\dfrac{16}{25}}\\\\x=-\dfrac{\sqrt{16}}{\sqrt{25}}\ \vee\ x=\dfrac{\sqrt{16}}{\sqrt{25}}\\\\\boxed{x=-\dfrac{4}{5}\ \vee\ x=\dfrac{4}{5}}$