Respuesta :
The keg for the reaction
2 SO2(g) + O2(g) → 2 SO3(g) is
Keg = [SO3]^2/ {(SO2)^2 ( O2)}
Keg (equilibrium constant) is the ratio of of equilibrium concentration of the product raised to the power of their stoichiometric coefficient to the equilibrium concentration of the reactant raised to the power of their stoichiometric coefficient.
2 SO2(g) + O2(g) → 2 SO3(g) is
Keg = [SO3]^2/ {(SO2)^2 ( O2)}
Keg (equilibrium constant) is the ratio of of equilibrium concentration of the product raised to the power of their stoichiometric coefficient to the equilibrium concentration of the reactant raised to the power of their stoichiometric coefficient.
Answer: The [tex]K_{eq}[/tex] for the reaction is [tex]K_{eq}=\frac{[SO_3]^2}{[SO_2]^2[O_2]}[/tex]
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients. It is represented by [tex]K_{eq}[/tex]
For a general chemical reaction:
[tex]aA+bB\rightarrow cC+dD[/tex]
The [tex]K_{eq}[/tex] is written as:
[tex]K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}[/tex]
For the given chemical reaction:
[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)[/tex]
The [tex]K_{eq}[/tex] is represented as:
[tex]K_{eq}=\frac{[SO_3]^2}{[SO_2]^2[O_2]}[/tex]
Hence, the equilibrium constant for the reaction is given above.