Respuesta :

Hi there!

Substitute the value " h = 2 " in th' expression :-

[tex]\dfrac {-(4h - 1)}{1 + h}[/tex] = [tex]\dfrac {-(4 × 2 - 1)}{1 + 2}[/tex] = [tex]\dfrac {-(8 - 1)}{3}[/tex] = [tex]\dfrac {-(7)}{3}[/tex] = [tex]\dfrac {- 7}{3}[/tex]

Hence, The required answer is : [tex]\dfrac {- 7}{3}[/tex]

~ Hope it helps!
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