Question

What is the true solution to the equation below? ln e^lnx^2=2 ln 8? A.x=2. B.x=4. C.x=8. D.x=64

Answer 1

$a^{\log_ax}=x\\\\log_ab^n=n\cdot\log_ab$


$x \ \textgreater \ 0\\\\e^{\ln x^2}=2\ln8\\\\x^2=2\ln2^3\\\\x^2=3\cdot2\ln2\\\\x^2=6\ln2\to x=\sqrt{6\ln2}$

Answer 2

The answer is X=4, B