The expression is [tex]A=g^2 + 14g + 40[/tex].
[tex]D=14^2-4\cdot 40=196-160=36 \\ \sqrt{D}=6 \\ q_{1,2}= \dfrac{-14\pm 6}{2} =-4,-10[/tex].
Then [tex]A=g^2 + 14g + 40=(g+4)(g+10)[/tex].
The width is g+4, the length is g+10.
When g=5,
g+4=9 ft and g+10=15 ft.
Answer: correct choice is D.